Evaluate using a substitution: lim x->2+ of arctan((1/(x-2))
\[\lim_{x \rightarrow 2+} \arctan (\frac{ 1 }{ x-2 })\]
so what happens if you substitute x with 2?
The number inside the parenthesis becomes undefined (1/0)
and what is the arctangent of undefined?
okay... here's a hint: \[\tan = \frac{\sin}{\cos}\] that will become undefined if cosine is 0... so what value of x will make cos x = 0?
pi/2 makes cos x =0
right. \[\tan (\frac \pi 2) = \frac{\sin (\frac \pi 2)}{\cos ( \frac \pi 2)} \implies \tan (\frac \pi 2) = \frac 10 \implies \text{undefined}\] do you get it now?
I understand that but how does this help if its arctan?
if the tangent of pi/2 is undefined...then what do you think is the arctangent of undefined?
OHHH its pi/2
indeed
But like is that how i wud show work? Like on an exam instead of reasoning with teh tangent is tehre a way to show taht its indeed pi/2?
actually..you don't ahve to show the solution of the tangent...arctangent of (1/0) is already automatic
i just showed you the solution of the tangent for you to see
B/C im supposed to evaluate using subsition. So what shud I write on paper as my work then?
Wait is like arctan of undefined always pi/2 b/c thats just smthg we need to memorize just like sin(90) = 1
THANKS NEVER MIND I GET IT :D
arctan (undefined) is not automatic 90 degrees by the way... it's 90 degrees in this case ebcause the numerator is 1 and 1 can only be got with sin (90)
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