Let g(s)=(5s−4)8.
Then g′(s) is________
and g′′(s) is _______
I dont know why I cant get the right answer for this question....

Question

Let g(s)=(5s−4)8.
Then g′(s) is________
and g′′(s) is _______
I dont know why I cant get the right answer for this question....

anonymous · Answer

g prime of (s) is 5(8) which = 40 and you cant take the derivative of 40

anonymous · Answer

well, i believe the derivative of a constant is 0. so g''(5s-4)8=0

anonymous · Answer

the first derivative is indeed 40. i hope this helps. :)

anonymous · Answer

oh wait I made a typo! Sorry guys! that is supposed to be to the power of 8 not x 8

anonymous · Answer

(5s-4)^8

anonymous · Answer

so if y=x^8, what is y'=?

anonymous · Answer

you have to use the chain rule for the problem

anonymous · Answer

i made a mistake in mine

anonymous · Answer

forgot your exponents

anonymous · Answer

ooooo and that's because the brackets counts as one part and the power as another, is that correct? Thats why the chain rule applies?

anonymous · Answer

yes

anonymous · Answer

that is why i was gonna start you with x^8

anonymous · Answer

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