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Let g(s)=(5s−4)8. Then g′(s) is________ and g′′(s) is _______ I dont know why I cant get the right answer for this question....
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g prime of (s) is 5(8) which = 40 and you cant take the derivative of 40
well, i believe the derivative of a constant is 0. so g''(5s-4)8=0
the first derivative is indeed 40. i hope this helps. :)
oh wait I made a typo! Sorry guys! that is supposed to be to the power of 8 not x 8
(5s-4)^8
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so if y=x^8, what is y'=?
you have to use the chain rule for the problem
i made a mistake in mine
forgot your exponents
ooooo and that's because the brackets counts as one part and the power as another, is that correct? Thats why the chain rule applies?
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yes
that is why i was gonna start you with x^8
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