Question

Please help!

For the equation x2 + 3x + j = 0, find all the values of j such that the equation has two real number solutions. Show your work

Answer 1

Use the discriminant to find the values of j
\[b ^{2}-4ac > 0\] this implies 2 real and different roots
plug in the values of a, b and c
\[(3)^{2}-4(1 \times j) > 0\]
\[-4j>-9\]
\[j<\frac{ -9 }{ -4 }\]
\[j<2.25\]