Question

point a is at 3r point b is at 2r from q determine elecric potential Vab in term of kq/r?

Answer 1

Vab=Va-Vb
We know potential is given by this relation at a distance r from a charge Q
\[V=\frac{KQ}{r}\]
\[V_a=\frac{KQ}{3r}\]
\[V_b=\frac{KQ}{2r}\]
\[Va< Vb\]
so
\[V_{ab}<0\]
Could you do it now?

Answer 2

i have solved but its -kq/6.where answer is required in r form

Answer 3

Vab=kq(1/2r-1/3r)
Vab=kq(3r-2r)/6r
=kqr/6r
=kq/6
I have solved like this

Answer 4

\[V_{ab}=kq(\frac{1}{3r}-\frac{1}{2r})\]
LCM of 2r and 3r is 6r
\[V_{ab}=kq\frac{2-3}{6r}\]
\[V_{ab}=-\frac{kq}{6r}\]

Answer 5

thanks you I was wrong in solving.

Answer 6

:D Welcome