Question

Determine the equation of the tangent line at the indicated x-coordinate.

f(x)=e^−1.1x⋅ln(5x) for x=2.
The equation of the tangent line in slope-intercept form is
y=

Answer 1

are you familiar with the derivative rule of e^f(x) and the natural logarithm derivative rule?

Answer 2

for d/dx i got -1.1e^-1.1x(ln5x)+(1/x)(e^-1.1)

Answer 3

^ is that correct?

Answer 4

one sec

Answer 5

oh yeah product rule. sorry

Answer 6

yes

Answer 7

soo why doesnt y=.024305x+.206524

Answer 8

\[= -1.1e^{-1.1}(\ln(5x))+\frac{1}{x}e^{-1.1}\]

Answer 9

@ =2...

Answer 10

ahh i think i found my careless mistake

Answer 11

ok nvm..

Answer 12

so r u still stuck?

Answer 13

yea

Answer 14

i got y=.447083x-.639031

Answer 15

why isnt ^ right?

Answer 16

help :c anyone