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Please help >__< Balance the following half-reactions by adding the appropriate number of electrons. I2(s)+6H20(l) -> 2IO3-(aq) + 12H+(aq)
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Thank you for answering!! :D
\[I _{2}(s) + 6H _{2}O(l) \rightarrow 2IO _{3 }^{-}(aq) + 12 H ^{+} + 10e ^{-}\]
wow.. thank you..!!!!
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