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Mathematics 19 Online
OpenStudy (anonymous):

Solve the linear inequality and express your answer in interval notation. 91 < |39 - {13}/{3}x |

OpenStudy (anonymous):

Please?

OpenStudy (anonymous):

Hello there. Any ideas?

OpenStudy (anonymous):

So...I'm guessing I should begin by subtracting 39 from both sides.

OpenStudy (anonymous):

No, really...

OpenStudy (anonymous):

What were you going to propose?

OpenStudy (anonymous):

?

OpenStudy (anonymous):

Wonderful. There you are.

OpenStudy (anonymous):

Any ideas?

hartnn (hartnn):

|x|>a means x>a OR x<-a so what 2 equation u get for 91 < |39 - {13}/{3}x | ??

hartnn (hartnn):

u can remove the mod sign || after breaking it into 2 equations

OpenStudy (anonymous):

Yeah, yeah...sorry

OpenStudy (anonymous):

91 < 39 - {13}/{3}x and 39 - {13}/{3}x < -91. There.

OpenStudy (anonymous):

I guess my biggest problem is with the fact that 13/3 is the coefficient.

hartnn (hartnn):

now those are just normal equations, try to isolate x from them

OpenStudy (anonymous):

So, I've simplified them. Now I have -13x = 234 and 13x = -312

OpenStudy (anonymous):

Which...is apparently not right.

OpenStudy (anonymous):

At least (-inf,-18) U (24,inf) and (-18,24) are wrong.

hartnn (hartnn):

91 < 39 - {13}/{3}x 91-39 < -13/3 x 52 < -13/3 x 156 < -13 x 12 < -x -12> x x< -12 got this part ?

OpenStudy (anonymous):

Yes.

hartnn (hartnn):

do it similarly for 39 - {13}/{3}x < -91.

OpenStudy (anonymous):

-13x < -130, -13x/-13 < -130/-13, x > 10

hartnn (hartnn):

x> 130*3/13 x> 30

OpenStudy (anonymous):

Ohhh....

OpenStudy (anonymous):

Thank you so much (again) hartnn!

OpenStudy (anonymous):

See you!

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