Mathematics
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OpenStudy (anonymous):
Solve the linear inequality and express your answer in interval notation.
91 < |39 - {13}/{3}x |
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OpenStudy (anonymous):
Please?
OpenStudy (anonymous):
Hello there. Any ideas?
OpenStudy (anonymous):
So...I'm guessing I should begin by subtracting 39 from both sides.
OpenStudy (anonymous):
No, really...
OpenStudy (anonymous):
What were you going to propose?
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OpenStudy (anonymous):
?
OpenStudy (anonymous):
Wonderful. There you are.
OpenStudy (anonymous):
Any ideas?
hartnn (hartnn):
|x|>a
means
x>a OR x<-a
so what 2 equation u get for 91 < |39 - {13}/{3}x | ??
hartnn (hartnn):
u can remove the mod sign || after breaking it into 2 equations
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OpenStudy (anonymous):
Yeah, yeah...sorry
OpenStudy (anonymous):
91 < 39 - {13}/{3}x and 39 - {13}/{3}x < -91. There.
OpenStudy (anonymous):
I guess my biggest problem is with the fact that 13/3 is the coefficient.
hartnn (hartnn):
now those are just normal equations, try to isolate x from them
OpenStudy (anonymous):
So, I've simplified them. Now I have -13x = 234 and 13x = -312
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OpenStudy (anonymous):
Which...is apparently not right.
OpenStudy (anonymous):
At least (-inf,-18) U (24,inf) and (-18,24) are wrong.
hartnn (hartnn):
91 < 39 - {13}/{3}x
91-39 < -13/3 x
52 < -13/3 x
156 < -13 x
12 < -x
-12> x
x< -12
got this part ?
OpenStudy (anonymous):
Yes.
hartnn (hartnn):
do it similarly for 39 - {13}/{3}x < -91.
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OpenStudy (anonymous):
-13x < -130, -13x/-13 < -130/-13, x > 10
hartnn (hartnn):
x> 130*3/13
x> 30
OpenStudy (anonymous):
Ohhh....
OpenStudy (anonymous):
Thank you so much (again) hartnn!
OpenStudy (anonymous):
See you!