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number of reams of paper: 0, 1, 2, 3, 4, 5 probability of using that amount: 0.05, 0.15, 0.40, 0.20, 0.10, 0.10 Find the standard deviation of the number of reams found at the end of the day?
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Standard deviation of a probability distribution is given by\[\sigma =\sqrt{\sum_{}^{}(X -\mu)^{2}P(X)}\][xP(x)]\]where x is the number of reams of paper and P(x) is the probability of using that number of reams of paper. Try it now and see if you get it.
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