Mathematics
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OpenStudy (anonymous):
Does any one have any clue about SloVing This ?
(・_・)
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OpenStudy (anonymous):
\[x-2y ^{2} = 3 e^{\pi/y}\] -_-
OpenStudy (anonymous):
Solve what?
OpenStudy (anonymous):
ohh yeah im trying to Find the derevative of \[y \prime (x)\]
OpenStudy (anonymous):
Use implicit differentiation.
OpenStudy (anonymous):
Thats nOt helPing =.=
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OpenStudy (anonymous):
Differentiate with respect to y.
OpenStudy (anonymous):
ohhh okie .. let me try
just wait i want to u to see the result ^_^'
OpenStudy (anonymous):
it will take time i guess >_ >
OpenStudy (anonymous):
So...:
1-4yy'= 3(e^(pi/y)*(pi/y^2))(y')
OpenStudy (anonymous):
I might have messed up because I am doing this all in my head.
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OpenStudy (anonymous):
Solve for y' and you have your answer.
hartnn (hartnn):
i wonder how of of that she understood...u should have let her tried first,dido
OpenStudy (anonymous):
Good point. I need sleep. Its 2am here.
OpenStudy (anonymous):
I dont usually post answers outright.
OpenStudy (anonymous):
( ・_・) i got my answer .. and it different than yours
\[x-4y = 3 e ^{x/y} x/y y \prime\]
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hartnn (hartnn):
take one term at a time, what is d/dx(x) ??
OpenStudy (anonymous):
Dido is a sleepyhead :B .. like me XP
OpenStudy (anonymous):
what ?
OpenStudy (anonymous):
Night... I have chemistry class tomorrow...
hartnn (hartnn):
1st term is x , what is its derivative ?
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OpenStudy (anonymous):
:] good night
OpenStudy (anonymous):
okie hartnn wait
=0=
OpenStudy (anonymous):
its \[x-4yy \prime \] ?
hartnn (hartnn):
d/dx (x) =1, not x
hartnn (hartnn):
1-4yy'
ok?
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OpenStudy (anonymous):
oh yeah ur right .. ma bad -..-' sorry
OpenStudy (anonymous):
so its 4y y prime
OpenStudy (anonymous):
- 4yy prim
OpenStudy (anonymous):
^,^'
hartnn (hartnn):
now diff, 3e^(pi/y)
u know how ?
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hartnn (hartnn):
heard of chain rule ?
OpenStudy (anonymous):
yup .. just wait
OpenStudy (anonymous):
yeah i know last week's leason
OpenStudy (anonymous):
its \[3e ^{\Pi/y} \pi/y y \prime \]
right :] ?
OpenStudy (anonymous):
Solve for y' and you have your answer.
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OpenStudy (anonymous):
I might have messed up because I am doing this all in my head.
OpenStudy (anonymous):
So...:
1-4yy'= 3(e^(pi/y)*(pi/y^2))(y')
OpenStudy (anonymous):
Differentiate with respect to y.
OpenStudy (anonymous):
Use implicit differentiation.
hartnn (hartnn):
u have to diff (pi/y) in the middle
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OpenStudy (anonymous):
O_0' what da heel .. that man is repeating him self =.='
go to sleep mr
=.=
OpenStudy (anonymous):
i already did mr.hartnn
OpenStudy (anonymous):
8]
hartnn (hartnn):
3e^(pi/y) d/dx(pi/y)
what is d/dx(pi/y) ??
OpenStudy (anonymous):
oh yeah >_ <' sorry sorry i remember now :P
wait :B
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OpenStudy (anonymous):
its ( ・_・) .....
\[3e ^{x/y}\frac{ y-xyy \prime }{y ^{2} }\]
OpenStudy (anonymous):
wrong ? ( -_-)
hartnn (hartnn):
u took x!
it is pi...
OpenStudy (anonymous):
Omg .. im gonna die TT_TT
hartnn (hartnn):
plz don't die ,not before solving this!
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OpenStudy (anonymous):
so the whole tem is zero :] ?
OpenStudy (anonymous):
-0-
hartnn (hartnn):
no, d/dx(pi/y) = pi d/dx(1/y)
= pi (-1/y^2 ) y'
getting these steps ?
OpenStudy (anonymous):
no pi is just a number .. so its zero when we differentiate it
hartnn (hartnn):
d/dx(ax) = a d/dx(x)
constant comes out when multiplied, doesn't go to 0
they go to zero when they are alone..
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OpenStudy (anonymous):
[>_<]9
OpenStudy (anonymous):
okie .. let me try again >_ >'
OpenStudy (anonymous):
y' = [3e^(x/y)*y-y^2]/[3e^(x/y)*x-6y^4]
OpenStudy (anonymous):
Acually the question is \[e ^{x/y} \] not \[ e^{\pi/y}\]
(^_^')7
OpenStudy (anonymous):
=.=
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hartnn (hartnn):
oh!!!....
OpenStudy (anonymous):
@Alice_Dump is my answer right???
OpenStudy (anonymous):
So the answer is \[1 - yy \prime = 3e ^{x/y} \frac{ y-xyy \prime }{ y ^{2}}\]
OpenStudy (anonymous):
@bhaskarbabu Not its noT >_ >'
OpenStudy (anonymous):
from where u got 6 and four -.-'
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OpenStudy (anonymous):
in simplification
hartnn (hartnn):
4 was there from beginning
OpenStudy (anonymous):
=..= i d k maybe right maybe wrong =..=
OpenStudy (anonymous):
is my answer right ?
\[1-4yy \prime = 3e ^{x/y} \frac{ y-xyy \prime }{ y ^{2}}\]
hartnn (hartnn):
but u need to isolate y' now
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OpenStudy (anonymous):
okie wait .
OpenStudy (anonymous):
@Alice_Dump sorry they should be 4 n3
0
y' = [3e^(x/y)*y-y^2]/[3e^(x/y)*x-4y^3]
OpenStudy (anonymous):
@Alice_Dump (y-xyy') should be (y-xy')
OpenStudy (anonymous):
=.=" wait
OpenStudy (anonymous):
and i bet its wrong T_T
\[y \prime = \frac{ 3e ^{x/y} y-1 }{ -4+xy y ^{-2}}\] >_ >'
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OpenStudy (anonymous):
HelloW .. anyone Here lo_ol
hartnn (hartnn):
try again
OpenStudy (anonymous):
derivative of y = y' or yy'
its y'
OpenStudy (anonymous):
O M G TT_TT this is killing meeh >:[
OpenStudy (anonymous):
@Alice_Dump according to u its yy' its wrong
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OpenStudy (anonymous):
where ? okie okie i will do it One more Time -.-
OpenStudy (anonymous):
one last TimE >:O
OpenStudy (anonymous):
Its \[y \prime =\frac{ 3e ^{x/y} y -1}{-4y + xy y ^{-2} }\]
again TT_TT Same answer .... l ̄д ̄l/ Kill meeeeh
OpenStudy (anonymous):
k iwil show u wait
OpenStudy (anonymous):
-。-'
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OpenStudy (anonymous):
(×× )/ me is stupid 8}
OpenStudy (anonymous):
>_ < what is the answer =.='
OpenStudy (anonymous):
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