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Mathematics 15 Online
OpenStudy (anonymous):

Does any one have any clue about SloVing This ? (・_・)

OpenStudy (anonymous):

\[x-2y ^{2} = 3 e^{\pi/y}\] -_-

OpenStudy (anonymous):

Solve what?

OpenStudy (anonymous):

ohh yeah im trying to Find the derevative of \[y \prime (x)\]

OpenStudy (anonymous):

Use implicit differentiation.

OpenStudy (anonymous):

Thats nOt helPing =.=

OpenStudy (anonymous):

Differentiate with respect to y.

OpenStudy (anonymous):

ohhh okie .. let me try just wait i want to u to see the result ^_^'

OpenStudy (anonymous):

it will take time i guess >_ >

OpenStudy (anonymous):

So...: 1-4yy'= 3(e^(pi/y)*(pi/y^2))(y')

OpenStudy (anonymous):

I might have messed up because I am doing this all in my head.

OpenStudy (anonymous):

Solve for y' and you have your answer.

hartnn (hartnn):

i wonder how of of that she understood...u should have let her tried first,dido

OpenStudy (anonymous):

Good point. I need sleep. Its 2am here.

OpenStudy (anonymous):

I dont usually post answers outright.

OpenStudy (anonymous):

( ・_・) i got my answer .. and it different than yours \[x-4y = 3 e ^{x/y} x/y y \prime\]

hartnn (hartnn):

take one term at a time, what is d/dx(x) ??

OpenStudy (anonymous):

Dido is a sleepyhead :B .. like me XP

OpenStudy (anonymous):

what ?

OpenStudy (anonymous):

Night... I have chemistry class tomorrow...

hartnn (hartnn):

1st term is x , what is its derivative ?

OpenStudy (anonymous):

:] good night

OpenStudy (anonymous):

okie hartnn wait =0=

OpenStudy (anonymous):

its \[x-4yy \prime \] ?

hartnn (hartnn):

d/dx (x) =1, not x

hartnn (hartnn):

1-4yy' ok?

OpenStudy (anonymous):

oh yeah ur right .. ma bad -..-' sorry

OpenStudy (anonymous):

so its 4y y prime

OpenStudy (anonymous):

- 4yy prim

OpenStudy (anonymous):

^,^'

hartnn (hartnn):

now diff, 3e^(pi/y) u know how ?

hartnn (hartnn):

heard of chain rule ?

OpenStudy (anonymous):

yup .. just wait

OpenStudy (anonymous):

yeah i know last week's leason

OpenStudy (anonymous):

its \[3e ^{\Pi/y} \pi/y y \prime \] right :] ?

OpenStudy (anonymous):

Solve for y' and you have your answer.

OpenStudy (anonymous):

I might have messed up because I am doing this all in my head.

OpenStudy (anonymous):

So...: 1-4yy'= 3(e^(pi/y)*(pi/y^2))(y')

OpenStudy (anonymous):

Differentiate with respect to y.

OpenStudy (anonymous):

Use implicit differentiation.

hartnn (hartnn):

u have to diff (pi/y) in the middle

OpenStudy (anonymous):

O_0' what da heel .. that man is repeating him self =.=' go to sleep mr =.=

OpenStudy (anonymous):

i already did mr.hartnn

OpenStudy (anonymous):

8]

hartnn (hartnn):

3e^(pi/y) d/dx(pi/y) what is d/dx(pi/y) ??

OpenStudy (anonymous):

oh yeah >_ <' sorry sorry i remember now :P wait :B

OpenStudy (anonymous):

its ( ・_・) ..... \[3e ^{x/y}\frac{ y-xyy \prime }{y ^{2} }\]

OpenStudy (anonymous):

wrong ? ( -_-)

hartnn (hartnn):

u took x! it is pi...

OpenStudy (anonymous):

Omg .. im gonna die TT_TT

hartnn (hartnn):

plz don't die ,not before solving this!

OpenStudy (anonymous):

so the whole tem is zero :] ?

OpenStudy (anonymous):

-0-

hartnn (hartnn):

no, d/dx(pi/y) = pi d/dx(1/y) = pi (-1/y^2 ) y' getting these steps ?

OpenStudy (anonymous):

no pi is just a number .. so its zero when we differentiate it

hartnn (hartnn):

d/dx(ax) = a d/dx(x) constant comes out when multiplied, doesn't go to 0 they go to zero when they are alone..

OpenStudy (anonymous):

[>_<]9

OpenStudy (anonymous):

okie .. let me try again >_ >'

OpenStudy (anonymous):

y' = [3e^(x/y)*y-y^2]/[3e^(x/y)*x-6y^4]

OpenStudy (anonymous):

Acually the question is \[e ^{x/y} \] not \[ e^{\pi/y}\] (^_^')7

OpenStudy (anonymous):

=.=

hartnn (hartnn):

oh!!!....

OpenStudy (anonymous):

@Alice_Dump is my answer right???

OpenStudy (anonymous):

So the answer is \[1 - yy \prime = 3e ^{x/y} \frac{ y-xyy \prime }{ y ^{2}}\]

OpenStudy (anonymous):

@bhaskarbabu Not its noT >_ >'

OpenStudy (anonymous):

from where u got 6 and four -.-'

OpenStudy (anonymous):

in simplification

hartnn (hartnn):

4 was there from beginning

OpenStudy (anonymous):

=..= i d k maybe right maybe wrong =..=

OpenStudy (anonymous):

is my answer right ? \[1-4yy \prime = 3e ^{x/y} \frac{ y-xyy \prime }{ y ^{2}}\]

hartnn (hartnn):

but u need to isolate y' now

OpenStudy (anonymous):

okie wait .

OpenStudy (anonymous):

@Alice_Dump sorry they should be 4 n3 0 y' = [3e^(x/y)*y-y^2]/[3e^(x/y)*x-4y^3]

OpenStudy (anonymous):

@Alice_Dump (y-xyy') should be (y-xy')

OpenStudy (anonymous):

=.=" wait

OpenStudy (anonymous):

and i bet its wrong T_T \[y \prime = \frac{ 3e ^{x/y} y-1 }{ -4+xy y ^{-2}}\] >_ >'

OpenStudy (anonymous):

HelloW .. anyone Here lo_ol

hartnn (hartnn):

try again

OpenStudy (anonymous):

derivative of y = y' or yy' its y'

OpenStudy (anonymous):

O M G TT_TT this is killing meeh >:[

OpenStudy (anonymous):

@Alice_Dump according to u its yy' its wrong

OpenStudy (anonymous):

where ? okie okie i will do it One more Time -.-

OpenStudy (anonymous):

one last TimE >:O

OpenStudy (anonymous):

Its \[y \prime =\frac{ 3e ^{x/y} y -1}{-4y + xy y ^{-2} }\] again TT_TT Same answer .... l ̄д ̄l/ Kill meeeeh

OpenStudy (anonymous):

k iwil show u wait

OpenStudy (anonymous):

-。-'

OpenStudy (anonymous):

(×× )/ me is stupid 8}

OpenStudy (anonymous):

>_ < what is the answer =.='

OpenStudy (anonymous):

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