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The Question IS >> FinD the tangent line of \[y ^{2} + xe ^{y} = 4- x \] at (2,0)
First differentiate the given equation to find dy/dx Then use slope-point equation of a line
And i Got htis answer >>\[y=\frac{ (-1-e ^{y}) (x-2) }{2y+e ^{y} }\] >_> '
\[y \prime =\frac{ -1-e ^{y} }{ 2y+e ^{y} }\]
In the denominator, its 2y + x(e^y)
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aha .. :l
So, that is the slope... Now find the equation of line
u know, you don't actually 'have to' find and isolate y' for this...
i did .. i found the equation for the tangent line =.=
|dw:1349825181883:dw|
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