Question

Type the first equation from the group you selected and identify the slope and the
y-intercept of the equation.


Type the second equation from the group you selected and change the equation into slope-intercept form. Be sure to show all of your work. Identify the slope and y-intercept of the equation.
Describe how you would graph this line using the slope-intercept method. Be sure to write in complete sentences.

y = negative three-halves x + 4 here is the equation

–3x + 2y = 8 both of them

Answer 1

i really need help im confused

Answer 2

What group are you talking about? And what do you mean at the end by both of them?

Answer 3

thoses are the 2 functions that i have to work with would you like me to put it in a doc so it is easyer to read

Answer 4

Sure let's see the doc.

Answer 5

Alright, so your selection is Group 1. Correct?!

Answer 6

what ever one is better i thought one but what ever one you would like

Answer 7

It's all the same to me. You make the choice or if you prefer, you can choose one group and I'll select a different group which I'll use as an example to teach you. What do you think? Sound good?

Answer 8

that seems fine @calculusfunctions

Answer 9

ok i guess you can teach me group 2 and ill do group one because that is the one that i am assined to by my teacher

Answer 10

Excellent!

Group 2:\[y =x -2\]and\[-2x +3y =-6\]
Now the question asks to identify the slope and y-intercept of the first equation:\[y =x -2\]The slope y- intercept form of the equation of a line is given by\[y =mx +b\]where m is the slope of the line and b is the y-intercept of the line. Thus if \[y =x -2\]then are you now able to identify the slope and the y-intercept value?

Answer 11

i think it might be 2x

Answer 12

No @mikala1, I said m is the slope> Not mx. Want to try again?

Answer 13

im not joking when i say i dont understand this i have a vary hard time at math i dont just want the answer like other people i appretiate your helping me and yes plaese

Answer 14

Alrighty then, no worries! I appreciate your honesty. I'm here for you! It's my job to teach and your job to ask questions and learn. So we have\[y =1x -2\]Now compare that with the general equation\[y =mx +b\]so the slope is m implies that the slope is the coefficient of x (the number in front of the variable x). Hence if\[y =x -2\]which is the same as writing\[y =1x -2\]then the slope must be 1 because in this equation the coefficient of x (the number in front of the variable x) is 1. Let me know when you've had a Eureka! moment.

Answer 15

oh ok ive got this ok thank you

Answer 16

Now b is the y-intercept so can you tell me what the y-intercept in that equation would be?

Answer 17

b

Answer 18

ok well thank you for ur time i understand alot of it now ik u probeble have other things to do so u can stop helping when ever oyu would like

Answer 19

Yes but in \[y =x -2\]what is the y-intercept? Sorry my computer lost the connection for a second there.

Answer 20

Compare the general linear equation with\[y =x -2\]

Answer 21

x - 2 right since its y = x 2 or 1

Answer 22

The y-intercept in\[y =mx +b\]is b (the constant or the number independent of the variable x, which means its the term without the x). Thus in \[y =x -2\]the constant term (the term independent of the variable x or the term without the x) is -2 right? Therefore the y-intercept is -2. Do you understand?

Answer 23

yes i do and u should be a teacher lol ur really good at it

Answer 24

now on the fist one that you did with me is that the full question and answer because im using that as an example but did we finish it

Answer 25

Thank you so much? Now let's discuss the next part of the question shall we?
Question 3 says:
"Describe how you would graph this line using the slope-intercept method. Be sure to write in complete sentences."
Let me ask you if have graph paper in front of you. Do you?

Answer 26

no she says we have to do it on the computer

Answer 27

and i said thank you

Answer 28

Oh I see! Do you know how to?

Answer 29

no not really i was going to call her for help

Answer 30

Yes you're very welcome but please there is absolutely no need to say thank you. A teachers greatest reward and thank you is when a student achieves proper understanding and success.

Answer 31

could you also help me with number 4 for the first one we did please

Answer 32

The fact that you had a Eureka or a aha moment and now able to answer the questions is what makes me happy. Therefore that is my thanks, which means more than any words you can say.

Answer 33

Of course! Let me read #4.

Answer 34

ok thank you

Answer 35

did you leave???

Answer 36

Again with the thank you. lol
Question 4:
"Type the second equation from the group you selected and change the equation into slope-intercept form. Be sure to show all of your work. Identify the slope and y-intercept of the equation."

So here the second equation is\[-2x +3y =-6\]Now we are asked to rearrange and express this equation in\[y =mx +b\]form. Do you notice that the left side of the equation has y only and the right side of the equation has the x term and the constant? Good, so then first rearrange\[-2x +3y =-6\]so that there is only the y term (3y) on the left side of the equal sign. To do this all you have to do really is add the opposite of -2x to both sides of the equation. Thus if\[-2x +3y =-6\]then\[3y =2x -6\]Hence we're almost there. Now the reason why it's still incomplete is because we still have 3y on the left side of the equal sign, and we want only. Since 3y means 3 "multiplied by" y, we will divide both sides of\[3y =2x -6\]by 3 (because the inverse operation of multiplication is division, which means division undoes multiplication). Hence if we divide both sides by 3, we obtain\[\frac{ 3y }{ 3 }=\frac{ 2 }{ 3 }x -\frac{ 6 }{ 3 }\]Now simplify to yield\[y =\frac{ 2 }{ 3 }x -2\] Thus the slope of this line is \[\frac{ 2 }{ 3 }\]because that is the number in front of the variable x, and the y-intercept of the line is\[-2\]because that is the term without the x.

Do you understand?

Answer 37

yes that is much simpler than what i thought it would be and another things is im sorry for keeping you but what would be the graphing points for this do you happen to know???

Answer 38

Sorry, my computer disconnected on me again right in the middle of my response so give me a few minutes because I have to start over again.

Answer 39

thats ok take ur time no hurry

Answer 40

They asked us to graph using the the slope-intercept method, right? So

i). plot the y-int. For example, in both our equations, the y-int. was -2. Thus first plot the point (0, -2).

ii). Now use the slope which is\[\frac{ rise }{ run }\]to help locate a couple or a few more points. In our first equation the slope was 1. This implies that there is a rise of 1 unit and a run of 1 unit. Thus starting from the point of the y-int. simply go 1 unit up and 1 unit to the right to plot the second point. Now from this second point, you may once again, go i unit up and 1 unit right to plot the third plot. You can do this as many times as you wish but just try to stay within the margins of your grid. Note that you may also go 1 unit down and 1 unit left (opposite of 1 up and 1 right) from the point of the y-int.

In our second equation, the slope was 2/3. This implies that there is a rise of 2 units up and a run of 3 units to the right. Thus starting from the point of the y-int. go 2 up and 3 right or the opposite of 2 down and 3 left to locate subsequent points.

iii). Once you have a few points, simply take a ruler and draw a straight line through passing through the points. Put arrows at the end and label the equation besides the graph.


Do you understand?

Answer 41

thank you so much now only i have to find a ruleer lol

Answer 42

If that's all for now, I have to go. But before I do, are you absolutely certain, you fully understand the lesson and that you will be fine answering the questions on your own now?

Answer 43

yes and im sorrry that i took so long to understand it

Answer 44

You're too polite. There is no need for you to be sorry. If you need my help with anything else involving math then I'll be back later. I'm not sure when bu if you see that I'm on and you need help, just try to catch my attention. Alright? Goodbye for now!

Answer 45

ok have a great day lol