Suppose that a sphere with radius 5a has the same volume as a cone of radius 3a. What is the height of the cone? Give your answer in terms of a. Use the formulas (Posted below) for the volume of a sphere and cone respectively.
(a) is a variable right?
yes
But I need someone to show me how to solve it step by step
Guys before I explain anything but is the height of the cone is 11.08
U mean you don't understand this from the prior question? "cancel pi and 3, and put r=3a for cone and r= 5a for sphere solve for h"
I am just asking whether the answer is 11
I dont know how to solve for h
@Faris_Waleed Yes, I am asking the question poster...
The answer will be in terms of a
OK, we have 4/3 * pi * r^3 = 1/3 * pi * r^2 * h and we can cancel pi and 3 -> 4* r^3 = r^2* h Ok up to here?
yes
Now we put 5a and 3a in for the "r's" 4*(5a)^3 = (3a)^2 * h OK?
yes im right with you
So h = 4* (5a)^3 /(3a)^2 = 600a^3 / 9a^2 = 200a/3 Done.
ok can you help me choose the answer now cause what you wrote i dont see on my paper
Wait a minute , it is 500 n ot 600
h = 4* (5a)^3 /(3a)^2 = 500a^3 / 9a^2 = 500a/9 Done.
A. 9/500a B. 500/9a^2 C.9/500a^2 D. 500/9a
I already did it above...
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