Question

What is the remainder of (x^3-6x-9x+3) divided by (x-3)

Answer 1

(x^3-6x-9x+3) is it (x^3-6x^2-9x+3)?

Answer 2

do you know how to divide ? or use synthetic division?

Answer 3

its the first on you put @surdawi

Answer 4

one

Answer 5

and phi yes i do but idk how to divide like this

Answer 6

when you have time,
http://www.khanacademy.org/math/algebra/polynomials/v/algebraic-long-division

Answer 7

ok thanks phi

Answer 8

p(x)=(x^3-6x-9x+3

p(3) = (x^3-6x-9x+3

Answer 9

Substitute x=3 in the eq and Find the remainder....Using..Remainder theorem..)

Answer 10

27 - 18 - 27 + 3

Answer 11

yahoo you see the (divided by) (x-3) right

Answer 12

Can someone help

Answer 13

A. -51
B. -51/x-3
C. -17/x
D. -17/x-3

Answer 14

the question has a type, it must be :
x^3-6x^2-9x+3

u do what yahoo said, u would get some answer thats there in options

Answer 15

hold on and i will show you the ?

Answer 16

yea

Answer 17

\[(x^{2}-6x-9x+3)\div(x-3)\]

Answer 18

if this question is correct, then we wont get any of the given answer choices

Answer 19

\((x^{2}-6x^2-9x+3)\div(x-3) \)

Answer 20

agree with ganeshine

Answer 21

it should be like above, plz check wid ur teacher

Answer 22

wait a sec.

Answer 23

\[x^{3}-6x-9x+3)\div(x-3)\]

Answer 24

now that question i just posted it correct

Answer 25

so that means it is x^3 - 15x + 3

Answer 26

i guess

Answer 27

ok are the solutions
A. -51 B. -51/x-3

or
A. -15
B. -15/x-3

Answer 28

A. -51 B. -51/x-3

Answer 29

ok then it should be
x^3-6*x^2-9*x+3 other wise it should be written in the book as x^3-15x+3

and the answer will be -51/x-3

if it is x^3-6x-9x+3
you will get -15/x-3

Answer 30

ok thank you so much this one was really crazy

Answer 31

it wasnt too crazy, you just forgot the ^2 :p

Answer 32

lol i know :)