Question

count_digits:
(str) -> int

Return the total number of characters in the given string that are digits.


can anybody help me come up with a python code for this problem?

Answer 1

I don't know if I get the question right, but for the number of characters just an "x = str(raw_input('ask: '))" and a "for" loop with an increasing variable.

Answer 2

i need to count the number of digits within the string ignoring regular characters

so if i wrote the word as kdfisfosdu32432

only the 32432 should be counted
resulting in the answer 5 (as number of digits)

Answer 3

Sorry for delay, should be something like this then??
x = raw_input("ingresa algo: ")
ans = 0
for i in x:
if (i == '0'):
ans += 1
elif (i == '1'):
ans += 1
elif (i == '2'):
ans += 1
elif (i == '3'):
ans += 1
elif (i == '4'):
ans += 1
elif (i == '5'):
ans += 1
elif (i == '6'):
ans += 1
elif (i == '7'):
ans += 1
elif (i == '8'):
ans += 1
elif (i == '9'):
ans += 1
print ans

Is kinda rough, I'll try to make it simpler

Answer 4

Going through it, I don't know how to make it simpler xD

Answer 5

i dont think i can use that

Answer 6

its too much aha

Answer 7

hahaha it's kinda annoying I know, but you can make it a function :P

Answer 8

i made this

def count_digits(word):
count = 0
for i in str(word):
if i.isdigit():
count +=1
print (count)

my only problem is say i do

count_digits(ds23)

instead of saying there is 2 digits

it says

count_digits(ds23)
Traceback (most recent call last):
File "<pyshell#81>", line 1, in <module>
count_digits(ds23)
NameError: name 'ds23' is not defined

Answer 9

what can i do to fix that so i can put letters and numbers in the sam thing and the code will just register the count of numbers

Answer 10

i know i have to make my variable word be a definitive string but how would i go about doing that?

Answer 11

Have you made the function "isdigit()" ?? if is made you should do something like:
if i == isdigit(i)

Answer 12

Have you put any single quotes around 'ds23'?

Answer 13

All are treated as strings, that's why you can't make something simple like this:
for i in x:
if type(i) == int:
ans += 1

Answer 14

you could do this
def count_digits(word):
count = 0
for c in word:
for i in range(0,10):
if str(i)==c:
count +=1
print (count)

Answer 15

http://dpaste.com/811789/

Answer 16

msmithhnova the idea was without and "str()" xD