Given the bond dissociation energies of X-X and Y-Y bonds, how can one find the pond dissociation energy of an X-Y bond?

For example, if we are given the bond dissociation energies of N-N and H-H, how can one find the bond dissociation energy of the N-H bond?

Thanks in advance! :)

Question

Given the bond dissociation energies of X-X and Y-Y bonds, how can one find the pond dissociation energy of an X-Y bond? 

For example, if we are given the bond dissociation energies of N-N and H-H, how can one find the bond dissociation energy of the N-H bond? 

Thanks in advance! :)

anonymous · Answer

The bond enthalpy/energy is the energy required to break 1 mole of a specified bond for a gaseous species at 298K/25oC. (note gaseous species are specified)

i.e. A-B(g) ==> A(g) + B(g)    ΔHBE(A-B) = + ??? kJmol-1
The diagram above shows, in terms of a dot and cross diagram, the breaking of a C-Cl bond by homolytic bond fission.

Note that bond breaking is always endothermic (+) and bond formation is always exothermic (-).

anonymous · Answer

http://www.cem.msu.edu/~reusch/OrgPage/bndenrgy.htm

anonymous · Answer

go through this table @ahaanomegas