Question

integral of 1/(sqrt(36-100x^2))dx

Answer 1

\[\int\limits_{}^{}\frac{ du }{ \sqrt{a^2-u^2} } = \arcsin(\frac{ u }{ a }) +C\]

Answer 2

does this help ?

Answer 3

yes! im just confused with what to do with 100. Do i take it out of the integral?

Answer 4

using this formula and let
a = 6
u = 10x

you see that
a^2 = 36
u^2 = 100x^2

so it is exactly the form of the integral up there ..

Answer 5

ok thank you!! I was making it more complicated then it needed to be

Answer 6

yes .. :)