Question

Find the derivative for me people .. i need help om im gonna fail in math =]

y(x)= tan power one (cos(2x))

Answer 1

this place is quite useful :) .. i need my answer now please

Answer 2

\[y(x)=tan(cos(2x))\]

There are a few things you need to know here.
One of the important ones is chain rule.
\[f(x) = g(h(x))\]
\[f'(x) = g'(h(x))*h'(x)\]
Now, let us look at your equation.
your f(x) = tan(cos(2x))
your h(x) = cos(2x)
if you take the derivative of tan(x), you'll get sec^2(x)
\[\frac{dtan(x)}{dx}=sec^2(x)\]
Now that you know what the derivative of tan(x) is, the same thing will apply to your function, however, there's a chain rule effect.
You must multiply by the derivative of the h(x)=cos(2x)

NOTE: when you take the derviate of h(x)=cos(2x) you must apply chain rule on the 2x

Answer 3

yeah yeah i see .. thanks man

Answer 4

but i still need the answer ..

Answer 5

Why don't you show me your answer, and perhaps your work and I'll walk you through it. If you truly only want an answer and not want to learn, you can google math programs that'll spit out derivatives for you.

Answer 6

im Solving it .. but u need to check the answer for me

Answer 7

type your answer and your work and I'll confirm if it's correct

Answer 8

k cool

Answer 9

i got

y prime (x) = -2 sec square ( cos 2x) sin (2x)

what do u think ?

Answer 10

yeah but here is 2x not x ,, but still not sure of my answer :P

Answer 11

its y prime (x) = -2 sec square ( cos 2x) sin (2x) and i know it
:/

Answer 12

your first answer is correct. well done

Answer 13

yeah k thanks anyway ;)

Answer 14

ipm1988 forgot to take into account that \[\frac{d}{dx}cos(2x)=-sin(2x)*\frac{d}{dx}(2x)\]

Answer 15

yeah yeah its a chain rule man , u can't just forget about any cuz its a connected chain

hehe just saying >_>

Answer 16

sorry it would be i again made a mistake just struck me \[-2\sec^2(\cos2x).\sin2x\]

Answer 17

aha

Answer 18

Step wise solution