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evaluate the integral (x^2 + 3)e^(3x+5) dx
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Are you supposed to use U substitution?
x^2e^(3x+5) + 3e^(3x+5) for the 3e^(3x+5) sub 3x + 5 = u then du = 3dx and i guess you can do it for x^2e^(3x+5) you should do integration by parts
So would the answer be (x+3) e(3x+5) ???
I meant e^(3x+5)
U= x^2 dV = e^(3x+5) dU =2x V= 1/3 e^(3x+5) \[\int\limits_{ }^{ } x ^{2}e ^{3x+5} dx = x ^{2}\frac{ 1 }{ 3 }e ^{3x+5} - \int\limits_{ }^{ } 2x\frac{ 1 }{ 3 }e ^{3x+5}dx\]
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see how the integral on the RHS is simpler than the one on the LHS?
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Yes, I see
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