Question

log2(a^2-6a)=log2(10+3a)

Answer 1

a^2-6a = 10+3a

solve for a

Answer 2

As the logs have the same base - 2 - we can say that the part in brackets on either side are equivalent i.e. \[a^2 - 6a = 10 +3a\]
From there we can solve for a;

\[a^2 - 6a - 3a -10 = 0\]
\[a^2 - 9a - 10 = 0\]
\[(a + 1)(a-10) = 0\]

So we can conclude that, \[a = -1\] & \[a = 10\] For this equality to work.