CAlculus Help!
find the derivative of the function.
g(x)=3arccos(x/2)
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OpenStudy (anonymous):
are u familiar with the derivative of \[\cos^{-1}\]
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
\[g(x)=3cos^{-1}(\frac{x}{2})\]
\[cos(\frac{g(x)}{3})=cos(cos^{-1}(\frac{x}{2})=\frac{x}{2}\]
if you take the derivative of that, you can find your answer much easier using chain rule without having to memorize arccos derviatives.
OpenStudy (anonymous):
\[g'(x) = 3[-\frac{1/2}{\sqrt{1-(\frac{1}{2})^{2}}}]\]
that took a while, but this is how i'm learning to do these derivatives
OpenStudy (anonymous):
but i HAVE to memorize the arccos derivatives!
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OpenStudy (anonymous):
umm okay can u exaplin step by step? pleas?
OpenStudy (anonymous):
2le or me?
OpenStudy (anonymous):
i mean explain?
OpenStudy (anonymous):
well you take the derivative and plug in the the values to the formula.
OpenStudy (anonymous):
why did u take out the 3?
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OpenStudy (anonymous):
the (3) is the constant multiple rule
OpenStudy (anonymous):
its a constant being multiplied so its carried out
OpenStudy (anonymous):
o okay. :]
OpenStudy (anonymous):
wait and the 1/2? y is it on top?
OpenStudy (anonymous):
so why is the 1/2 on top again?
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