Question

3/8X+3/8=-3/8X+1/8

Answer 1

3/8X+3/8=-3/8X+1/8

Answer 2

x=-3

Answer 3

make the LCM 8x on both sides,so that they can cancel, then the equation becomes;
3+3x=-3+x
now u can get x=-3

Answer 4

math2!
you'd better use some parentheses to clarify! Which one do you mean?
1. \[\frac{ 3 }{ 8x }+\frac{ 3 }{ 8 }=-\frac{ 3 }{ 8x }+\frac{ 1 }{ 8 }\]
2. \[\frac{ 3 }{ 8 }x+\frac{ 3 }{ 8 }=-\frac{ 3 }{ 8 }x+\frac{ 1 }{ 8 }\]
It could go on either ways. But most likely, what you mean is the second one. If so, you must do as follows:
1. Multiply all terms by 8 in order to cancel all 8's in denominators. Then it will be like this: \[3x+3=-3x+1\] Then \[3x+3x=1-3\rightarrow 6x=-2\rightarrow x=-\frac{ 1 }{ 3 }\]

Answer 5

MathPhysics i think you just changed the question

Answer 6

pasta! Why are you saying this?!!
Quite the contrary, I think this is you who did so!!

Answer 7

I THINK THE "X" IS PART OF THE DENOMINATOR NOT THE NUMERATOR

Answer 8

Might be! If you read my post carefully, you'd notice that I already mentioned it. He hasn't determined what he exactly meant.

Anyways, If he meant the first possibility I mentioned, you'd be right then.