Question

Please help me find the derivative of the following problem...

Answer 1

\[y=\ln (4-xe ^{-x})\]

Answer 2

i am now at this point....

Answer 3

\[=\frac{ 1 }{ \ln(4-xe^{-1}) }\times \frac{ d }{ dx }[4-xe ^{-x}]\]

Answer 4

oops
the derivative of \(\ln(f(x))\) is \(\frac{f'(x)}{f(x)}\)

Answer 5

in other words, your denominator should be \(4-xe^{-x}\) and your numerator should be the derivative of \(4-xe^{-x}\)
for that you will need the product rule and the chain rule

Answer 6

oh ya, oops. should not have put the natural log in the denominator

Answer 7

other than that it is essentially the same at this point correct?