Molarity question: you have 695 mL of a o.61 M solution of nitric acid. what is the weight of the nitric acid in solution. 27 g
so you have 0.61 M M= n/L ... so you have 0.61 moles of HNO3 in 1 L of water.. 0.61 mol/L x 63g/mol = 38.43 g/L you have a volume of 0.695 L.. 38.43 g/L x 0.695 L = 26.71 g of HNO3
what about 27g? I dont need to use this mass?
i think that was the answer
Thank you :) could you help with other question? 66.32 g Pb(So4)2 are dissolved into a 1350 mL solution and 136.2 g FeSo4 are dissloved into a 980 mL solution. which solution contains a higher molarity of sulfate ion?
ill tell you how to do it, how bout that? find the number of moles then find molarity .. wait are you sure it's Pb(SO4)2? not PbSO4
so yeah, find moles in each solution.. n=m/MW then find molarity M=n/L which ever one is higher wins
thanks, MW stands for mass weight?
molecular weight or molecular mass
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