Question

Divide
z^2-9z+14 by z-7
plz show me how to do this

Answer 1

try starting by factoring the top:
\[\frac{ z^2-9z+14 }{ z-7 } = \frac{ (z-7)(z-2) }{ (z-7) }\]

Answer 2

does that help get you started?

Answer 3

ok, i'll try

Answer 4

??

Answer 5

use long division. the answer is z-2

Answer 6

ok

Answer 7

z-2 is correct. I am not sure about the long division technique, but in this example, since you could factor and cancel the (z-7) terms, it allowed you to get z-2... that is correct here.

@arisauotani might be able to elaborate on long division technique...

Answer 8

what about the 9z+14 ?

Answer 9

my webassign shows z-2 to be incorrect ??

Answer 10

z^2 -9z + 14 is equal to (z-2)(z-7)... if you multiply out those parenthesis terms, you will get z^2 - 2z - 7z + 14, and the two middle terms simplify to - 9z

So on the top of the fraction you have (z-2)(z-7)
and on the bottom, you have (z-7)
so when you cancel, the (z-7) terms go away and leave (z-2) alone on top.

I can't imagine why your website shows z-2 to be incorrect. Is there any more information given in the problem or the directions.

Answer 11

Divide z2 − 9z + 14by z − 7.

Answer 12

z^2

Answer 13

thats the question

Answer 14

OMG....Im soo SORRY i typed in a capital z, thats why it didnt take it.
it took it now. Thank u soo much

Answer 15

that's so so so annoying, isn't it!!

Answer 16

glad you figured it out though :) Good luck!

Answer 17

thank u