A bit of a calculus / physics question!

So when we graph velocity (distance/time) versus time, and we take the derivative of this function, we get an acceleration function. If we graph position (just distance) versus time squared, and we take the derivative - do we still get an acceleration function...?

Question

A bit of a calculus / physics question!

So when we graph velocity (distance/time) versus time, and we take the derivative of this function, we get an acceleration function. If we graph position (just distance) versus time squared, and we take the derivative - do we still get an acceleration function...?

anonymous · Answer

distance vs time squared is acceleration.
taking the derivative of this would be the rate of change in acceleration

anonymous · Answer

Thanks for your help! Can you explain more about this link: http://wiki.answers.com/Q/What_does_the_slope_of_a_distance_vs_time_squared_graph_represent and why the slope of a distance vs time-squared graph is one HALF acceleration?