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differential to estimate the value (26)^(2/3)
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The answer is 8.78. I used my calculator.
i guess you are supposed to use \(27\) since \(27^{\frac{2}{3}}=9\)
idea is to linearize \[\sqrt[3]{(27-x)^2}\] and then replace \(x\) by 1
Use differentials to estimate the value of the indicated expression. Then compare your estimate with the result given by a calculator.
take the derivative, replace \(x\) by 27 to find the slope, then use the point slope formula to find the equation of the line tangent to the graph of \(y=\sqrt[3](27-x)^2}\) at the point \((27,9)\)
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that should be \(y=\sqrt[3]{27-x)^2} \)
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