Question

last one! need help verifying
1 - tan cos/ csc = cos^2

Answer 1

\[1-\frac{ \tan(x)\cos(x) }{ \csc(x) }=1-\frac{ \frac{ \sin(x) }{ \cos(x) }\cos(x) }{ \frac{ 1 }{ \sin(x) } }\]\[=1-\sin^{2}x=\cos^{2}x\]

Answer 2

you need some parenthesis

Answer 3

@Zekarias can you explain what you did?

Answer 4

wright tan(x) and csc(x) as sin(x)/cos(x) and 1/sin(x), first.
Can u do that?

Answer 5

yes

Answer 6

Then cancel cos(x) with cos (x). What will u have?

Answer 7

you'll have 1 - sin divided by 1/sin

Answer 8

what is sin(x)/1/sin(x)?

Answer 9

sin^2

Answer 10

1-sin^2(x) = cos ^2(x) wright?

Answer 11

oh i understand now! its on eof the identities!

Answer 12

thank you!