Question

This is to Shravanm1, squareroot of 7-2x-square root x+2=squareroot x+5, using substitution

Answer 1

\[\sqrt{7-2x}-\sqrt{x+2}=\sqrt{x+5}\]

Answer 2

Let's see you solve it tough guy...use substitution

Answer 3

substitution? why?

Answer 4

why not?

Answer 5

you can't use substitution rani...you only gave me one equation

Answer 6

well your in "Calculus 3", solve it great one

Answer 7

i can solve it, just not with substitution. that's not possible with the given information

Answer 8

then use square the root

Answer 9

oh really? how so?

Answer 10

thats better!

Answer 11

then how come I did it?

Answer 12

when you square both sides, you get:
((7-2x)-(2)(sqrt7-2x)(sqrtx+2)+(x+2))=x+5

Answer 13

how'd you do it with substitution rani? show me??

Answer 14

you did an error, you have to remove the sqrts

Answer 15

but not bad ;), i believe you

Answer 16

Nope. Not yet.

Answer 17

the formula is: (a+b)^2=a^2+2ab+b^2

Answer 18

ahhh, good good... you cannot use substitution and your not supposed to remove the sqr roots. lol

Answer 19

finish it and let's see

Answer 20

yeah from there you'd move the free expressions to the left, leaving the two square roots, then solve. its a lot of work and i cant really draw it out

Answer 21

one question, are there square roots on (7-2x) and (x+2)? ;)

Answer 22

Yes, in the middle term(2ab)

Answer 23

im pretty sure on the left and right also

Answer 24

when you square a square root, it becomes normal

Answer 25

so is it going to be 49-4x?? or 7-2x?