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find dy/dx y=(sinxcosx)secx
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what property/rule?
rewrite as \(\sin(x)\) and it should be easy
product?
The product rule extends to D(f(x)g(x)h(x))= f'gh+fg'h+fgh'
\[\sec(x)=\frac{1}{\cos(x)}\] so you are looking at \(y=\sin(x)\)
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sec(x) = 1/cos(x), so sin(x)cos(x)*[1/cos(x)) = sin(x) Now, just find d/dx sin(x) = cos(x)
Thank you!
y'=sec2x
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