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Mathematics 8 Online
OpenStudy (anonymous):

find dy/dx y=(sinxcosx)secx

OpenStudy (anonymous):

what property/rule?

OpenStudy (anonymous):

rewrite as \(\sin(x)\) and it should be easy

OpenStudy (anonymous):

product?

OpenStudy (anonymous):

The product rule extends to D(f(x)g(x)h(x))= f'gh+fg'h+fgh'

OpenStudy (anonymous):

\[\sec(x)=\frac{1}{\cos(x)}\] so you are looking at \(y=\sin(x)\)

OpenStudy (kirbykirby):

sec(x) = 1/cos(x), so sin(x)cos(x)*[1/cos(x)) = sin(x) Now, just find d/dx sin(x) = cos(x)

OpenStudy (anonymous):

Thank you!

OpenStudy (anonymous):

y'=sec2x

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