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OpenStudy (anonymous):
Find the derivative
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OpenStudy (anonymous):
\[t^{3/2} (2+\sqrt{t})\]
OpenStudy (turingtest):
do you know the derivative of t^(2/3) ?
OpenStudy (turingtest):
t^(3/2)
excuse me....
OpenStudy (anonymous):
3/2t^3?
OpenStudy (anonymous):
do you know how to apply the product rule and power rule?
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OpenStudy (anonymous):
yea
OpenStudy (anonymous):
i just have trouble finding the derivative for the square root. i got -1/2x, i'm not sure if that's right
OpenStudy (anonymous):
almost right.
OpenStudy (anonymous):
sqroot t = t^(1/2)
OpenStudy (anonymous):
that's the derivative? isn't that the same as square root of t?
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OpenStudy (anonymous):
but with an exponent?
OpenStudy (anonymous):
yea, so apply the power rule to find the derivative
OpenStudy (anonymous):
f * g' + f' * g -> t^3/2 * t^1/2 + 3/2t^3 * ? are you sure that is the derivative of square root of t?
OpenStudy (anonymous):
no, i was just showing you that square root t can be rewritten like that. apply the product rule to find the derivative of sq root t
OpenStudy (anonymous):
but that's what i have problems with? i got 1/2x as the derivative of square root of t
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OpenStudy (anonymous):
dx^1/2/dx = (x^[-1/2])/2
OpenStudy (anonymous):
= 1/(2x^[1/2])
OpenStudy (anonymous):
|dw:1349841522489:dw|
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