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Given the vectors b = Dr and c = xr, where r is the position vector and D is a constant, calculate (Curl) :∇ × b and ∇ × c
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∇ × b = D∇×r + ∇DXr can you do it now ?
i have to go so ill give the answer ∇ × b = ∇ × Dr = D∇×r + ∇DXr -> if you check ∇×r = 0 so D∇×r = 0 and ∇D = 0 since its constant so ∇ × b = 0 ∇ × c = ∇ × xr = x∇×r + ∇x X r = 0 + ∇x X r = (0,-z,y)
you can as well put the constant on the x right into the r vector and calculate the curl directly .. (instead of using my method)
was helpful, thank you
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