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Mathematics 19 Online
OpenStudy (anonymous):

Given the vectors b = Dr and c = xr, where r is the position vector and D is a constant, calculate (Curl) :∇ × b and ∇ × c

OpenStudy (anonymous):

∇ × b = D∇×r + ∇DXr can you do it now ?

OpenStudy (anonymous):

i have to go so ill give the answer ∇ × b = ∇ × Dr = D∇×r + ∇DXr -> if you check ∇×r = 0 so D∇×r = 0 and ∇D = 0 since its constant so ∇ × b = 0 ∇ × c = ∇ × xr = x∇×r + ∇x X r = 0 + ∇x X r = (0,-z,y)

OpenStudy (anonymous):

you can as well put the constant on the x right into the r vector and calculate the curl directly .. (instead of using my method)

OpenStudy (anonymous):

was helpful, thank you

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