How many grams of nitrogen are there in 5.0 grams of baking powder-(NH4)2CO3

Question

anonymous · Answer

2 nitrogen -  14.01*2=28 grams then

anonymous · Answer

ali000000 how can there be 28 g of nitrogen if he has only 5 g sample?!
now this is how i would do it:
first take mass (molar mass) of the molecule and just divide mass (molar mass) of nitrogen in that molecule (so it is 2*14,01) and divide those two numbers to get percentage of N in compound and than that you multiply that percentage with mass you got (5 g).

so it is:

2*M(N) / M((NH4)2CO3 = ???
and 
??? * 5 g = m(N) in that given sample...

anonymous · Answer

///first take mass (molar mass) of the molecule and just divide mass (molar mass) of nitrogen in that molecule (so it is 2*14,01)/// first take mass (molar mass) of the molecule and just (multiply )mass (molar mass) of nitrogen in that molecule (so it is 2*14,01), right? correct sir @kryten