Question

solve for y
x=y/(y-1)

Answer 1

ok i cant just give you the answer so ask a question or something

Answer 2

i can

Answer 3

can you assist me in walking through it?

Answer 4

well let me see

Answer 5

there are two ways

Answer 6

I get (y-1)x=y and i dont know what to do after that

Answer 7

this might help you http://mathway.com/answer.aspx?p=calg?p=xSMB01ySMB10(y-1)?p=1?p=?p=?p=?p=?p=0?p=?p=0?p=?p=?p=SolveSMB15theSMB15EquationSMB15forSMB15y

Answer 8

check it out

Answer 9

multiply them xy-x = y

Answer 10

did it help?

Answer 11

its telling me to create an account

Answer 12

xy-y = x
y(x-1) = x
y= x/x-1

Answer 13

reaally i thought if you just go in the link it will tell you something else let me see

Answer 14

y=x/x-1

Answer 15

thats what the page was supposed to say

Answer 16

so the starting equation was y=x/(x-1) and the inverse is the same?

Answer 17

looks like it

Answer 18

but the graph would look different.

Answer 19

right?

Answer 20

another way : x=y/y-1 ... flip them
1/x=(y-1)/y
1/x=y/y - 1/y ..... spread them
1/x = 1- 1/y
1/y=1-1/x
1/y = (x-1)/x
then y = x/x-1

Answer 21

about the graph ... i think so

Answer 22

like the point (3,1.5) should be (1.5,3)

Answer 23

thats why im so confused. I am getting the same equation that is supposed to be a different graph

Answer 24

wait a minute

Answer 25

this is one equation that we are talking about

Answer 26

sorry. i wasnt detailed in the original question. i needed to find the inverse of y=x/(x-1)

Answer 27

i just posted where i was getting stuck

Answer 28

did you get the inverse?

Answer 29

I cant figure it out. i was searching online and found one source that said it had no solution. I have no idea what it is

Answer 30

hmmm i think there is an inverse

Answer 31

thats what i was thinking as well. I am sure there is one. but its confusing

Answer 32

can you not just switch the y (s) for x ?

Answer 33

well i need to solve for y

Answer 34

then it becomes a circle

Answer 35

well this is quite the confusing problem then.

Answer 36

hmmm

Answer 37

try to sketch the two graphs