Question

Solve: cos(x)(cosx+1)=0

Answer 1

is it cos(x+1)?

Answer 2

or (cos x)+1

Answer 3

its (cosx+1)

Answer 4

like...i...said...

Answer 5

either cos(x) is 0 or cos(x+1) is 0

Answer 6

Set each to 0 and solve
\[\cos(x) = 0\]
\[\cos(x) + 1 = 0 or \cos(x) = -1\]

cos(x) is 0 when x is pi/2 3pi/2, 5pi/2 ect so the answer would be \[x = \frac{\pi}{2} +\pi*n\]
and cos(x) is -1 when x is pi, 3pi, 5pi,ect so the answer to that would be \[x = \pi + 2n*\pi\]

Answer 7

oh, i should mention, n is a integer value

Answer 8

The avalaible answers are
A. x = PI/3+-2PIn, x = 3PI/4+-2PIn
B. x = Pi/2+-2PIn, x = 3PI/2P-2PIn, x =Pi+-2PIn
C. x =+-PIn, x = Pi/2+-2PIn
D. x = Pi/2+-PIn, x = 3Pi/2+-2Pin

Answer 9

D

Answer 10

Wrong again but hey..tbh im not really surprized...everyone has given me wrong answers for the last 6 questions...why should i expect dif

Answer 11

wait hang on..

Answer 12

too late moving on

thnx anyways tho

Answer 13

It was b ._.

Answer 14

ohh, i see what they did in B. They did it weird.

Answer 15

yeah well..im starting to get pissed ...one question wrong occasionally im fine with....but the last 6 ..well now 7 have gotten wrong

Answer 16

in.a.row. .....

Answer 17

Life is tough