Question

Suppose that f(x)=4^(x^2+5x) Find f'(x0

Answer 1

Sorry ment find f'(x)

Answer 2

Pretty sure you can log this equation to get log(4)^(x^2+5x)
Then since its a log you can bring the exponent in front.
So we have (x^2 + 5x) log(4).
differentiate to get (2x + 5)log(4)

note: log(4) is just a number but multiplied so you leave it alone in the differentiation

Answer 3

That doesn't seem to be working for some reason.

Answer 4

its 4^(x^2+5x) log(4)^(x^2+5x)

something to do with the chain rule.