Question

Choose the slope-intercept equation of the line that passes through the point (-5, -1) and is perpendicular to y = 5/2x + 2.

Answer 1

y = 2/5x + 1

y = -5/2x - 27/2

y = -2/5x - 3

y = 5/2x + 23/2

Answer 2

@cwrw238

Answer 3

@ash2326

Answer 4

@Gabylovesyou did you try this?

Answer 5

yes but i dont get how to ...

Answer 6

Ok. Standard slope and intercept form equation of a line
\[y=mx+c\]
where m= slope
c= y-intercept
here we have a line
\[y=\frac 52 x+2\]
What is its slope?

Answer 7

to find the slope i have to.... ?

Answer 8

compare standard equation and the given equation.

Answer 9

do you get this?

Answer 10

mmm kinda

Answer 11

Read my second post again and compare to find the slope of the line

Answer 12

mmmmmmmmm can u do it step by step???

Answer 13

Should I given you an example?

Answer 14

yes please

Answer 15

suppose I have a line
\[y=5x+6\]
I need to find the slope
I'll compare it with the standard equation
\[y=mx+c\]
I see m=5 and c=6
so slope =5
and y- intercept=6
do you get this?

Answer 16

ok... mmm so slope is 5/2 ?

Answer 17

Yes

Answer 18

if two lines are perpendicular then
\[m1\times m2=-1\]
m1 and m2 are their slope respecticely
here m1= 5/2, what's m2?

Answer 19

2?

Answer 20

\[\frac 52 \times m2 =-1\]
\[m2=???\]

Answer 21

,,,, - 5/4 ?

Answer 22

@Gabylovesyou How you'd solve this?
\[\frac 1 2\times x=1\]

Answer 23

x = 2

Answer 24

solve this also the same way
\[\frac 52 \times m_2=-1\]

Answer 25

idk how too