Due to wind resistance, a car's gas mileage is inversely proportional to the square of its highway driving speed. A particular car gets 32 miles per gallon at a speed of 65 miles per hour. What gas mileage would it get for a speed of 75 miles per hour?
\[milage \alpha \frac{1}{speed^{2}}\] where the alpha symbol mean proportional and the fraction gives you the inverse (ie as the speed goes up the mileage goes down)
you can replace the alpha with and equals sign if you introduce a constant of proportionality:\[mileage = \frac{c}{speed^{2}}\]
By direct subtitution you can solve first the constance value of c (using the known values of 32mpg and 65mph). You can then use that same constant along with 75 mph to find the unknown mileage of the quesiton.
thanks :)
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