Question

Please help!
A landing airplane accelerates at -3.10 m/sec^2 down a 3.80 km runway. What is the fastest speed that the pilot could land and still stop at the end of the runway?

Answer 1

\[x = vt + \frac{1}{2}at^{2}\]

Answer 2

sorry that doesnt help give me a second

Answer 3

I am only given the acceleration and the distance... and I think I need to find the initial velocity

Answer 4

∆d = Vo*t + 1/2at^2.... maybe use this equation?

Answer 5

yeah exactly, you want an equation without time

Answer 6

Ahhh... V^2 = Vo^2 + 2a∆d

Answer 7

\[v^{2}=u^{2} + 2ax\]?

Answer 8

yeah that one