Question

what are the derivations of 3e^x-4^x?

Answer 1

the derivative of 3e^x is just 3e^x (it is it's own derivative)

the derivative of 4^x, don't quite remember... it has to do with lnx

Answer 2

yes its kinda hard ... well the 1st one is just 3e^x-4^x*(ln(4)
but the second one is harder .... help?

Answer 3

not sure what you mean by first and second

in the problem 3e^x - 4^x, the derivative would be

d/dx [3e^x] - d/dx [4^x]

the first derivative we already know, it's 3e^x

so now we have:

3e^x - d/dx [4^x]

checked book quick, and d/dx of 4^x is 4^x*ln4

so, the answer is:

3e^x - 4^x*ln4

which is what you had

Answer 4

most of the time you can get the derivative of the first derivative but this is impossible aaa! but thank you! I will share the answer once we walk through it in class.

Answer 5

ohhh, you want the second derivative?

well, it would just be:

3e^x - 4^x*ln4
d/dx [3e^x] - d/dx [4^x * ln4]
you need to use the power rule on the second term
f'g + g'f

3e^x - [4^x*ln4*ln4 + 4^x*1/4]
which equates to

3e^x - [4^x*(ln4)^2] - [4^x/4]

Answer 6

i meant product rule* not power rule

Answer 7

Yes this is exactly what i needed! Thank you!!!