Question

Add
(−5t^2 − t + 3.5) + (5t^2 + 3t − 1.2)

Answer 1

what do you think it is? it's very similar to the other problems you've posted

Answer 2

i was thinking 3t + 2?

Answer 3

not quite. the -5t^2 and 5t^2 cancel, as you have shown.

you're left with - t + 3t and 3.5 - 1.2

-t is just (-1)t

another way to think about it is (3-1) * t

3.5 - 1.2 is simple subtraction

Answer 4

2t + 2.3?

Answer 5

yep yep

Answer 6

thank you!! you're so helpful

Answer 7

do you know how to do this (−4a^2)(5a^5) sorry for asking you so many questions

Answer 8

lol that's fine, and yeah:

you can multiply exponentials together if the base is the same, for instance:

4^2 * 4^3 would be 4^5

keep the base the same, and add the exponents.

(−4a^2)(5a^5) would be like:

[-4 * 5] * [a^2 * a^5]

you can pull out the numbers in front, and just look at the base and exponent.

think you know it?

Answer 9

i got -20^7 but when i put that it said its wrong because i had to simplify it but i'm not so good at simplifying

Answer 10

-20a^7

you forgot to keep the a! unless that is a typo

there is no way to further simplify it... unless they want like:

-20a * -20a * -20a * -20a * -20a * -20a * -20a

[-20a multiplied by itself 7 times, which is what an exponent is]

Answer 11

ok i seee let me check because maybe i did forget the a

Answer 12

yea you were right i forgot it

Answer 13

haha it's all good

Answer 14

its probably gonna be like 4 more questions i ask u if i can't get them lol if thats ok with you but what about this one 7b4(3b2 − 3b)
when i did it i got 21b^6 - 21b idk

Answer 15

first part is right, second part, not quite.

7b^4 * -3b

is just -21 * b^(4+1)

b is just shorthand for what it really means: b^1

Answer 16

oooh ok didn't get that part so its 21b^5

Answer 17

yep

Answer 18

well -21b^5, don't forget the negative!

Answer 19

what about this one i have no idea what to do with it
(x + 2)(x2 − 2x + 4)
lol i feel like i'm asking too many questions

Answer 20

well, to solve something like that, you need to distribute all the terms.

it would be like:

x * x^2 - x*2x + 4*x + 2*x^2 - 2*2x + 4*2

see what i did there?

Answer 21

yes i see what you did but don't know how to solve it because its confusing

Answer 22

well technically you cant solve this, as it doesn't equal anything.

you are just un-factoring it.

all you have to do is collect like terms

it's just a lot of algebra

Answer 23

yea it is which is really confusing lol

Answer 24

try it and see what answer you get.

its a bit confusing, but just go term-by-term and eventually after doing a couple problems you can do it in your head

Answer 25

that x2 is supposed to be x^2

Answer 26

that's what i figured, i wrote it that way when i distributed it all

Answer 27

oh ok lol so the like factors would be 2 and 4? and idk what else

Answer 28

another way of thinking about this is like this:

(x + a) (x^2 + x + b)

is the same as

x * (x^2 + x + b) + a * (x^2 + x + b)

Answer 29

well, if the question is:

(x + 2)(x2 − 2x + 4) = 0

you can set x + 2 = 0 and x^2 - 2x + 4 = 0

x + 2 = 0 would juts be x = -2

however, you can't factor the second part, so you need to use the quadratic formula.

Answer 30

oh ok i see. i'm probably not going to get this question lol

Answer 31

do you know the quadratic formula?

Answer 32

a = 1, b = -2, and c = 4

Answer 33

not really is that the formula?

Answer 34

no the formula is