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5v-4\10=4\5
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\[\frac{ 5v-4 }{ 10 }=\frac{ 4 }{5 } ?\]
\[5v-4\div10=\frac{ 4 }{ 5 }\]
or \[5v-\frac{4 }{ 10 }=\frac{ 4 }{ 5 }\]
ok
the first one
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\[5v = \frac{ 4 }{5 } + \frac{ 4 }{ 10 }\rightarrow 5v = \frac{ 4*2 }{5*2 } + \frac{ 4 }{10 }\rightarrow v=\frac{ 12 }{10 } * \frac{ 1 }{5}\rightarrow v= \frac{ 6 }{ 25 }\]
is this a new problem?
yes
did you understand the last one?
yes
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\[12-\frac{ 4 }{ 5 }(x+15)+4\]
\[12-(\frac{ 4x }{5 } + 12) + 4\rightarrow 12-\frac{ 4x }{5 }-12+4\rightarrow4-\frac{ 4x }{ 5 } or \frac{ 20-4x }{5 }\]
I'm assuming the expression is just supposed to be simplified.
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6(3a+1)-30=3(2a-4)
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