Question

question about critical points when constructing a graph

Answer 1

What's the question?

Answer 2

ok, my fucntion is

Answer 3

\[\sqrt[3]{x^2-1}\]

Answer 4

the derivative is

Answer 5

\[\frac{ 2x }{ 3\sqrt[3]{(x^2-1)^2} }\]

Answer 6

Okay, so what's the question?

Answer 7

when i find the critical points, i set the numerator and denominator = 0 , or the entire f'(x)

Answer 8

or what is the best way to find critical points

Answer 9

i would say that the critical points are 0, +- 1

Answer 10

Okay, so you don't set the numerator or denominator to zero, but instead set the whole eqation to 0. Then you solve the equation.

Answer 11

ok, so my crit points would just be 0

Answer 12

If you could write out the original equation as a drawing, I could solve it. I can't really interpret the small numbers in the equation.

Answer 13

If your original equation is cuberoot(x^2-1), then critical point is only 0

Answer 14

yep :)