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Mathematics 18 Online
OpenStudy (anonymous):

Prove: (1 - tan²x)/(1 + tan²x) = 1 - 2sin²x

OpenStudy (anonymous):

replace the first 1 with sin^2x+cos^2x, this should make proving easier.

OpenStudy (anonymous):

@zordoloom, anymore insight you can offer? I've changed 1 + tan²x with sec²x, but I'm unsure if that's a step in the right direction. Once I get that, I change sec²x to 1/cos²x. That comes out to be: [(sin²x + cos²x) - tan²x]/(1/cos²x) What next?

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

change the den to sec^2x

OpenStudy (anonymous):

then change sec^2x to 1/cos^2x

OpenStudy (anonymous):

You should now have (1-tan^2x)/(1/cos^2x)

OpenStudy (anonymous):

now change 1-tan^2x to cos^2x

OpenStudy (anonymous):

now you should have cos^2(x)-sin^2(x).

OpenStudy (anonymous):

I'm sorry but I have to go now. I'll be late for my class. Maybe I can help you later.

OpenStudy (anonymous):

Thanks for what you've helped me with so far! I'll see if I can figure it out from here.

OpenStudy (anonymous):

|dw:1349911964222:dw|

OpenStudy (anonymous):

simple as that : )

OpenStudy (anonymous):

Much appreciated, epsilon!

OpenStudy (anonymous):

yw

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