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OpenStudy (anonymous):
replace the first 1 with sin^2x+cos^2x, this should make proving easier.
OpenStudy (anonymous):
@zordoloom, anymore insight you can offer? I've changed 1 + tan²x with sec²x, but I'm unsure if that's a step in the right direction.
Once I get that, I change sec²x to 1/cos²x.
That comes out to be:
[(sin²x + cos²x) - tan²x]/(1/cos²x)
What next?
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
change the den to sec^2x
OpenStudy (anonymous):
then change sec^2x to 1/cos^2x
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OpenStudy (anonymous):
You should now have (1-tan^2x)/(1/cos^2x)
OpenStudy (anonymous):
now change 1-tan^2x to cos^2x
OpenStudy (anonymous):
now you should have cos^2(x)-sin^2(x).
OpenStudy (anonymous):
I'm sorry but I have to go now. I'll be late for my class. Maybe I can help you later.
OpenStudy (anonymous):
Thanks for what you've helped me with so far!
I'll see if I can figure it out from here.
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