DEFINITE INTEGRAL
evaluate the definitie integral \[\int\limits_{2}^{-1} (3-2x^2) dx\]
a) by using the Riemann sum b) by using the fundemental theorem of calculous (definite integrals)
I don't understand how to do this at all so can someone please explain
does it matter which riemann sum you use?
I don't believe so
I don't undertstand what the heck x^* i is
I'm not sure what to explain
I don't understand where the i comes from in the equation or what x subscript i is
Do you understand the fundamental concept of integrals, which are evaluations of area?
I guess I just don't understand the terms and where they come from in Riemanns sum I understand that they are for evauluating area but I don't understand the equations given
the equations aren't very important; the subscript i denotes the "interval". I can understand where you're coming from. Sometimes the formulas seem unnecessary. It's like the difference quotient, though: you stop using it once you have a firm footing for an understanding of where integrals came from
does it matter wich riemann sum you use?
\[\sum_{i=1}^{n} \left[ (2--1)\div n \right] \left[ 3-2x^2) \right]\]
Would that be it????
am I a little bit close 3:
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