Question

Can someone explain what I have to do in this problem? (PROBLEM ATTACHED AS PICTURE IN REPLY)

Answer 1

Do I set V = F'', DV = x? Get du = F' dx, v = x^(2) / 2 ?

Answer 2

use uv formula. i.e. integral of product

Answer 3

yeah, is what I did correct?

Answer 4

http://en.wikipedia.org/wiki/Integration_by_parts

follow this link.

Answer 5

I'd do u=x, du=dx, dv=f''dx, v=f'

Answer 6

Integration by parts:
\[\large \int udv = uv - \int vdu\]

Answer 7

This is what I have right now:
XF' - int(F'dx)

Answer 8

I have 18 minutes left to do it =(.
How do you take the integral of F'dx?

Answer 9

The integral of f' is f.
Antiderivative of a derivative is the function.

Answer 10

Okay so I have: XF' - F now.

Answer 11

Good, now evaluate between your limits.

Answer 12

You are given the values, so just plug them in.

Answer 13

So that's going from 1 to 0.
[(1)(6) - 3) ] - [ (0)(whatever = becomes 0) - 5] = [6 - 3] - 5 = -2?

Answer 14

I think you forgot to distribute that minus sign to the -5.

Answer 15

Ah, you are right! I got it, it becomes 3 + 5 = 8. Thank you so much!

Answer 16

You're welcome.