Question

find d^2(y)/d(x^2) in terms of x and y (second derivative)
1-xy=x-y

Answer 1

\[1(\frac{ dy }{ dx })-(x)\frac{ dy }{ dx}+\frac{ dx }{dx }y=\frac{ dx }{ dx }-\frac{ dy }{ dx }\]
tell me how this looks it's been a while since I differentiated with this method.

Answer 2

this would be the setup to solve for the first derivative

Answer 3

y=-1 & y"=0

Answer 4

http://i.imgur.com/CMgMz.gif

Answer 5

mother of god...

Answer 6

how did u get the second derivative?
@mahmit2012

Answer 7

-( x*y' + y) = 1 -y'

Answer 8

solve for y'

Answer 9

differentiate the expression again

Answer 10

I didn't do the second derivative yet. just do the first then repeat.

Answer 11

if you get another y' in your expression for y"
sub.s in your result from the first differentiation...

Answer 12

Does that make sense?

Answer 13

y=-1 y"=0 why you did not pay attention!

Answer 14

x#1

Answer 15

i got y' is -y-1/x-1
then i tried doing quotient rule and thne i got confused

Answer 16

you fail at math @mahmit2012

Answer 17

k

Answer 18

you got y' right

Answer 19

every body sleeping !! cool

Answer 20

yeah -y-1/x-1

Answer 21

now, f = ( -y-1) g = (x-1)

(f/g)' = f'g -fg'/g^2

f' = -y'
g' = 1
g^2 = (x-1)^2

Answer 22

plug them in and use the result from the first diff. : y' = -y-1/x-1
to sub.s in for y'

Answer 23

find y=-1 it's so easy !!!

Answer 24

got it @blackrose636 ?

Answer 25

how did u even get y=-1?

Answer 26

gl @Callisto

Answer 27

y-xy=x-1
so y=-1 for all x#1

Answer 28

@Algebraic! did you get it !

Answer 29

Ah...
1 - xy = x-y
y-xy = x-1
y (1-x) = x-1
y = (x-1) / (1-x)
y=-1!

Answer 30

Thank you @Callisto

Answer 31

this is different seeing !