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Use Chain Rule to Solve F(x)=f(f(x) and G(x)=(F(x))^2. You also know that f(3)=8 f(8)=3 f'(8)=11 f'(3)=4. Find F'(3) and G'(3) I have been stuck on this for hours.
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differentiate F(x)= f(f(x))
F'(x)= f'(f(x)) f'(x)
now at x=3 F'(3)= f'(f(3)) f'(3)
So would it be 4*3*3?
F'(3)= f'(f(3)) f'(3) = f'(8)4= 11*4=44 do the same for other one
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fine?
Still a little lost on the G(x) one
So would it be 2(44)*11?
G(x)=(F(x))^2 G'(x)= 2 F(x)* F'(x) at x=3 G'(3)= 2 F(3)* F'(3) u know F'(3) =44 from previous question so u have to find F(3) only
use this for getting F(3) F(x)=f(f(x)
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does it help u?
So wait is it 44*44?
F(3)=f(f(3)) = f(8) =3 so G'(3)= 2 F(3)* F'(3)= 2 *3*44
I get it now thank you so much!
:)
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