Question

A rectangular raft of thickness 30cm and mass 120kg floats in water.The submerged depth is 16cm.What is the submerged depth when a student of mass 60kg gets on the raft? Te answer is 24cm but I have no idea how to solve it.Please explain in details.Thanks

Answer 1

180g = V*rho*g
find V
that's how much of the raft is submerged.

Answer 2

I dont get what you did thereCan you explain

Answer 3

we are looking for depth

Answer 4

sure, they tell you 120g = V*rho*g
they also say h(submerged) = .16
so area = 120/(.16rho)

Answer 5

use that in the equation:

180g = V*rho*g

where V = 120h/(.16rho)

Answer 6

area = 120/(.16rho)
?

Answer 7

yes.

Answer 8

I dont get where area cme from

Answer 9

what happend to g?

Answer 10

should it be v=120h/(0.16rhpg)

Answer 11

go for it.

Answer 12

did you get 24 cm?

Answer 13

wait

Answer 14

180g = (120h/(.16rho) )* rho*g

h= .16*(180/120)

Answer 15

I am totally confused

Answer 16

let me go step by step

Answer 17

(120)g=pvg

Answer 18

120=pv

Answer 19

120=pAH

Answer 20

A=120/(ph)

Answer 21

good so far.

Answer 22

180=ph

Answer 23

pv

Answer 24

180=pv

Answer 25

yes

Answer 26

180=pAH

Answer 27

180=A=120/(ph).P.h

Answer 28

180=A.120/(ph).P.h

Answer 29

i THINK THERE SHOULD BE AN EASIER WAY

Answer 30

lol

Answer 31

it is worth 0.5 point

Answer 32

I already did it the easy way.

Answer 33

look at it this way if you like

mass of the floating object is proportional to volume of water displaced

if the volume is something simple, like a rectangular prism, then the height submerged is proportional to volume submerged.

m2/m1 = V2/V1 = h2/h1 since the constants will cancel in every case.

(edited a few times for clarity)