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Mathematics 25 Online
OpenStudy (anonymous):

1. Give the coordinates of two points on the line x = 5. 2. Give the coordinates of two points on the line y = -2. 3. Write the equation of the horizontal line passing through the point (-1, -8). 4. Write the equation of the vertical line passing through the point (3, 1). 5. Is the line with equation x = 4 horizontal or vertical? What is the slope of this line? 6. Is the line with equation y = -8 horizontal or vertical? What is the slope of this line?

OpenStudy (darkprince14):

6. horizontal... slope = 0

OpenStudy (calculusfunctions):

Question 1: "Give the coordinates of two points on the line x = 5". Alright, so first tell me what you know about the line x = 5. Tell me everything you know.

OpenStudy (calculusfunctions):

@darkprince14, I would like @mikala to answer because she needs to learn. So please, if you don't mind. Thank you! @mikala1, are you there? Can you please tell me everythhing you know about the line x = 5?

OpenStudy (anonymous):

no not really i just strted this lesson this is my first time

OpenStudy (anonymous):

if you have to go then you can go i dont need them right now i was just asking

OpenStudy (darkprince14):

sorry..my bad XD...@mikalal , give it your best :)

OpenStudy (calculusfunctions):

Multiple Choice: Is the line x = 5 a). horizontal b). vertical c). diagonal

OpenStudy (anonymous):

i will but thanks for ur help umm i think the x on a graph goes up and down so thats virtical right

OpenStudy (anonymous):

you can draw it to see it more clearly

OpenStudy (anonymous):

so it could be 5,0 5,1 right since thoses are on five or ever 5,5

OpenStudy (calculusfunctions):

YES! x = 5 is a vertical line. Excellent! So what would the coordinates of two points on this vertical line be then?

OpenStudy (anonymous):

i said 5,0 5,5 i think

OpenStudy (calculusfunctions):

Yes! (5, 0) and (5, 1) are definitely amongst the infinite number of possibilities.

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

so on number 2 it could be -2,1 and -2,-2 right

OpenStudy (calculusfunctions):

Question 2: "Give the coordinates of two points on the line y = -2". Now what do you you know about the line y = 2. Are you able to answer this question now?

OpenStudy (calculusfunctions):

You type faster than I.

OpenStudy (calculusfunctions):

Sorry, I meant y = -2

OpenStudy (anonymous):

did ii get them right

OpenStudy (anonymous):

@calculusfunctions shouldn't it be written in coordinate form, being infinite?

OpenStudy (calculusfunctions):

No! this time your points are wrong. Try again please.

OpenStudy (anonymous):

well then idk what it is is it all positive

OpenStudy (calculusfunctions):

What type of line is y = -2?

OpenStudy (calculusfunctions):

Do you know?

OpenStudy (anonymous):

y

OpenStudy (anonymous):

axess

OpenStudy (calculusfunctions):

Is it a horizontal, vertical or a diagonal line?

OpenStudy (calculusfunctions):

If x = 5 was a vertical line then y = -2 is what type of line?

OpenStudy (anonymous):

horozantial

OpenStudy (calculusfunctions):

yes!

OpenStudy (calculusfunctions):

So then what are two possible points on this line?

OpenStudy (anonymous):

umm -2 and -1

OpenStudy (calculusfunctions):

No! @mikala1, let's put on our thinking caps for a second, shall we? If y = -2, then shouldn't the y-coordinate be always -2?

OpenStudy (anonymous):

ya thats what i put i thought

OpenStudy (calculusfunctions):

Any point is given by (x, y). You said (-2, -1). The correct response would have been (-1, -2). Do you see the difference?

OpenStudy (anonymous):

-2 and -2 right

OpenStudy (anonymous):

ya because of the x axxess

OpenStudy (calculusfunctions):

Yes (-2, -2) is correct because the y-coordinate is -2. Just so we're clear that you understand, can you please give me two more points? And can please write it properly. (-1, -2), NOT -1, -2. I need to see those parentheses please.

OpenStudy (anonymous):

|dw:1349954979257:dw| this might help

OpenStudy (anonymous):

yes sir (-3,-2) (-5,-2)

OpenStudy (anonymous):

thank you lambchop

OpenStudy (calculusfunctions):

Thank you @lambchamps. @mikala1, do you see the diagram @lambchamps was kind enough to provide? Please take a look. Does that help? Thank you again @lambchamps.

OpenStudy (anonymous):

np

OpenStudy (anonymous):

yes i did i type my things right this time and i said thatnk you

OpenStudy (calculusfunctions):

Question 3: "Write the equation of the horizontal line passing through the point (-1, -8)". Now do you know what to do here?

OpenStudy (calculusfunctions):

Sorry, yes of course. You're quite welcome, @mikala1.

OpenStudy (anonymous):

no and did i get number 2 right and no i dont understand

OpenStudy (calculusfunctions):

It's not necessary to keep saying thank you. The only thanks I need is knowing that you understand and that you have learned. That is the only reason I'm here.

OpenStudy (anonymous):

@calculusfunctions i think is safe to say that it's \[(5,\infty),(5, - \infty )\] isn't?

OpenStudy (calculusfunctions):

Yes, I believe I already confirmed that question 2 was correct.

OpenStudy (anonymous):

ok now number 3 ik nothing on so if you have to go then u can go because this is taking u to long andi fel bad

OpenStudy (calculusfunctions):

@lambchops, what is safe to say? You're talking about intervals, not points. That will just confuse her.

OpenStudy (anonymous):

oh sorry

OpenStudy (calculusfunctions):

Yes #3. What do you think equation of a horizontal line looks like?

OpenStudy (anonymous):

ya i was just like what the heak lol its ok lambchop keep helping though

OpenStudy (anonymous):

i have never even seen one

OpenStudy (calculusfunctions):

Go back and think about y = -2 again.

OpenStudy (anonymous):

ok

OpenStudy (calculusfunctions):

y = -2 represents a horizontal line where the y-coordinate of any point on the line is -2. So then how would you use this fact to answer Question 3?

OpenStudy (anonymous):

would it by y -1 and x 8

OpenStudy (anonymous):

i ment -8

OpenStudy (anonymous):

am i right

OpenStudy (anonymous):

tell her the slope int form

OpenStudy (anonymous):

r u dar

OpenStudy (calculusfunctions):

The equation of any vertical line is x = c where c is any constant and the x-coordinate of any point that the vertical line passes through. The slope of a vertical line is undefined. The equation of any horizontal line is y = c where c is any constant and the y-coordinate of any point that the horizontal line passes through. The slope of a horizontal line is zero. Now use this information to answer the question please.

OpenStudy (anonymous):

i am not understanding this sorry if you have to go u can go

OpenStudy (anonymous):

@lambchamps DO U UNDERSTAND THIS I DONT SORRY FOR THE CAPS

OpenStudy (calculusfunctions):

Equation of any diagonal (oblique) line is\[y =mx +b\]where m is the slope and b is the y-intercept. But I already explained that to you last time @mikala1. That's why I didn't include that in the notes above. But @lambchamps, mentioned it so I'm mentioning it again.

OpenStudy (anonymous):

no still not understandng orry i give up

OpenStudy (anonymous):

@mikala1 there you go @calculusfunctions has mentioned the formula

OpenStudy (calculusfunctions):

@mikala1, you're told that the horizontal line passes through (-1, -8), right? OK, since the y-coordinate of this point is -8, and it's a horizontal line, the equation is therefore\[y =-8\]Do you understand now?

OpenStudy (anonymous):

thats what i put dow in one of my responces and u never replied

OpenStudy (anonymous):

so x equals -1 right

OpenStudy (calculusfunctions):

I never saw that! @lambchamps, did you see that? Perhaps @mikala1, you shouldn't type while I'm typing, trying to teach you. It's causing a lot of confusion and wasting valuable time.

OpenStudy (anonymous):

well i have to go eat and the only one i need help on is number 4 the other 2 i now understand

OpenStudy (anonymous):

sorry about that i dident mean to wast your time

OpenStudy (anonymous):

@calculusfunctions nope

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