Question

(2/x+1) - (1/x^2-9)

Answer 1

and i should get that its not equal to 0.... but i dont get this...

Answer 2

\[\frac{ 2 }{ x+1} - \frac{ 1 }{ x^{2}- 9}\]
u mean this?

Answer 3

yes... how do you do this? :D

Answer 4

the equation button on the left of post

Answer 5

\[\frac{ 2 }{ x+1 } - \frac{ 1 }{ x ^{2}-9 } \neq 0\] this is it

Answer 6

and i need to find the meaning s of x i think

Answer 7

find LCD's first

Answer 8

what is lcd?

Answer 9

beats me...let's figure it out lol

Answer 10

i done like 30 similar thingies.... and i cant do this one (╯°□°)╯︵ ┻━┻

Answer 11

\[( x+1 )( x^{2} - 9)\]
\[x^{3} - 9x + x^{2} - 9\]
or: \[x^{3} + x^{2} - 9x -9\]

Answer 12

it looks a lot easier on paper...i swear it

Answer 13

but where the - in the middle of them dissapears?

Answer 14

define "them" ?

Answer 15

\[\frac{ 2 }{ x+1 } \] and \[\frac{ 1 }{ x ^{2} -9 }\] there was a minus thingy in the middle of them... where it dissapears?

Answer 16

all i did was find the LCD so it looks like
\[\frac{ 2 }{ x + 1 } * \frac{ x^2 - 9 }{ x^2 - 9 }\]
\[\frac{ 1 }{ x^ - 9 } * \frac{ x + 1 }{ x + 1 }\]
\[\frac{ 2x^2 - 18 }{ x^3 +x^2 -9x - 9 } - \frac{ x + 1 }{ x^3 + x^2 - 9x - 9 }\]

Answer 17

well thats what i did but i couldn't continue

Answer 18

who's asking this question? o.O

Answer 19

it was me... bu i still dont get it :D

Answer 20

well since they now have an LCD they can be subtracted like normal equations <3
\[\frac{ 2x^2 - x - 19 }{ x^3 + x^2 -9x -9 }\]